Could someone answer this please.. I am stumped. A Norman window has the shape of a rectangle with a semi circle on top; diameter of the semicircle exactly matches the width of the rectangle. Find the dimensions w x h of the Norman window whose perimeter is 600in that has maximal area. Could i get some help finding the height please? the picture will be in the reply section
Let me find some paper...
Let me give it to you as i go along...
So let P stand for perimeter P = 600 = h + h + w + w*pi/2 600 = 2h + w(1+pi/2) from this after a bit of tidying up, w = (1200 - 4h) / (2 + pi)
Now let A stand for Area (which we want to maximise) A = wh + [pi*(w/2)^2] / 2 A = wh + w^2 * pi / 8
This gets a bit messy (just saying)
i am really tired, so this is already hard to understand :)
Well it gets worse
Can i just give you the gist of it?
I also cannot be bothered typing in the rest
that sounds like a good idea. thank you.
So from the first bit, I got an expression for w in terms of h. We now have A, but in terms of w and h. We want to maximise A in terms of h, so we substitute our h's in A. Now we have an expression for A in terms of ONLY h. Great! Now after heaps of cleaning up, we get that A is a concave down quadratic in h. From this we know that there must be a maximum point, and we find this by using the formula: x = -b/(2a) in the quadratic 0 = ax^2 + bx + c and there you have it. This x value will be your height that causes the maximum area
wow... that is amazing that your brain can work like that. thank you
but what does b stand for?
Oh ax^2 + bx + c is the general expression for a quadratic. a, b and c are any real values (positive or NEGATIVE), which in your case A will be neg
but remember for the formula to work, ax^2 + bx + c must equal 0
okay thank you :)
No worries :D
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