Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

Could someone answer this please.. I am stumped. A Norman window has the shape of a rectangle with a semi circle on top; diameter of the semicircle exactly matches the width of the rectangle. Find the dimensions w x h of the Norman window whose perimeter is 600in that has maximal area. Could i get some help finding the height please? the picture will be in the reply section

OpenStudy (anonymous):

OpenStudy (anonymous):

Let me find some paper...

OpenStudy (anonymous):

Let me give it to you as i go along...

OpenStudy (anonymous):

So let P stand for perimeter P = 600 = h + h + w + w*pi/2 600 = 2h + w(1+pi/2) from this after a bit of tidying up, w = (1200 - 4h) / (2 + pi)

OpenStudy (anonymous):

Now let A stand for Area (which we want to maximise) A = wh + [pi*(w/2)^2] / 2 A = wh + w^2 * pi / 8

OpenStudy (anonymous):

This gets a bit messy (just saying)

OpenStudy (anonymous):

i am really tired, so this is already hard to understand :)

OpenStudy (anonymous):

Well it gets worse

OpenStudy (anonymous):

Can i just give you the gist of it?

OpenStudy (anonymous):

I also cannot be bothered typing in the rest

OpenStudy (anonymous):

that sounds like a good idea. thank you.

OpenStudy (anonymous):

So from the first bit, I got an expression for w in terms of h. We now have A, but in terms of w and h. We want to maximise A in terms of h, so we substitute our h's in A. Now we have an expression for A in terms of ONLY h. Great! Now after heaps of cleaning up, we get that A is a concave down quadratic in h. From this we know that there must be a maximum point, and we find this by using the formula: x = -b/(2a) in the quadratic 0 = ax^2 + bx + c and there you have it. This x value will be your height that causes the maximum area

OpenStudy (anonymous):

wow... that is amazing that your brain can work like that. thank you

OpenStudy (anonymous):

but what does b stand for?

OpenStudy (anonymous):

Oh ax^2 + bx + c is the general expression for a quadratic. a, b and c are any real values (positive or NEGATIVE), which in your case A will be neg

OpenStudy (anonymous):

but remember for the formula to work, ax^2 + bx + c must equal 0

OpenStudy (anonymous):

okay thank you :)

OpenStudy (anonymous):

No worries :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!