Question

Algebra help please! I do not get this.....

Simplify the expression..

\[27^\frac{ 1 }{ 3 }\]

Use the rules for exponents simplify the expression.

\[b\frac{ m }{ n }=n \sqrt{b}^m=(n \sqrt{b})^m\]

Answer 1

As if to support L66 ^_^
\[\huge a^{\frac{\color{red}m}{\color{green}n}}=\sqrt[\color{green}n]{a^{\color{red}m}}\]

Answer 2

ok, so let TJ help

Answer 3

Look closely at what happens to the numerator-exponent and denominator-exponent.

Answer 4

Oh no, I was only (technically) cheering for you L66 :)
Please continue XD

Answer 5

TJ I know you, you have a good way to explain, please, please, help him

Answer 6

Fine :3
@Dakotafox79
I want you to factor 27, completely, into primes...
Can you do that?

Answer 7

Erm, no. Sorrry for slow response laggy school pc....

Answer 8

You can't factor 27? :|
Very well, let's not do that XD

Use this rule...
\[\huge a^{\frac{\color{red}m}{\color{green}n}}=\sqrt[\color{green}n]{a^{\color{red}m}}\]

And in this instance...
\[\Huge 27^{\frac{\color{red}1}{\color{green}3}}=\color{blue}? \]

Answer 9

What do you get?
Use the drawing tool, if you don't know how to typeset equations yet ^_^

Answer 10

Hey, @Dakotafox79 Stuck?

Answer 11

\[\sqrt[3]{27}^1\]

Is that it ? Lol... God I suck at math. :/

Answer 12

That is correct :)
\[\Huge 27^{\frac{\color{red}1}{\color{green}3}}=\sqrt[\color{green}3]{27^\color{red}1}=\sqrt[3]{27}\]
L66 has taught you well...
Now... what's the cube root of 27? ^_^

Answer 13

3, right?

Answer 14

Brilliant :)

Answer 15

Now that wasn't so hard, was it?

Answer 16

Yay, thank you so much :D. And now that I look at it like this, not really that hard :) thanks so much!!!

Answer 17

Of course.
Might help you to remember that...
raising to an exponent 1/2 is the same as getting the square root...
raising to an exponent 1/3 is the same as getting cube root
raising to an exponent 1/4 is the same as getting fourth root...

etc

It'll save you time ^_^

Answer 18

Okay. Thanks again :)