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I can't get this. Solve this.
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bring all the terms and variables to one side!!
\[x/4+x/2-x+1>0\]
\[\frac{x}{4}+\frac{x}{2}>x-1\]\[\frac{x}{4}+\frac{x\color{red} {\times 2}}{2\color{red} {\times 2}}>x-1\]\[\frac{x}{4}+\frac{2x}{4}>x-1\]\[\frac{3x}{4}>x-1\]\[\frac{3x}{4}>\frac{\color{red} {4}x}{\color{red} {4}}-1\]\[\frac{3x}{4}\color{red} {-\frac{4x}{4}}>\frac{4x}{4}-1\color{red} {-\frac{4x}{4}}\]\[-\frac{x}{4}>-1\]x=?
My ans. is x < 4 .. Is that correct?
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fine I'll finish it. \[-\frac{x}{4}\color{red} {\times (-4)}>-1\color{red} {\times (-4)}\]flipe the sign when multiplying by a negative, and you get, \[\color{blue} {x~<~4~}\]
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