Use the function to answer the question. f(x) = 5x - 10 What is the value of f^–1 (–3)?
I got 12
lets test if its correct.. put x = 12 in f(x), do u get -3 ?
f(12) = 5*12 - 10 = 60 - 10 = 50 so, 12 is not right ok
ohh.... ok. OH, wait, sorry, I got 12 on another question. I don't know this one
to find f^–1 (–3), u need to solve x below :- -3 = 5x - 10 solve x
Ok, I got 1.4
x = 7/5 = 1.4 is \(\large \color{red}{\checkmark}\)
Ok, sweet. Thank you. Now is this 12? Use the functions to answer the question. f(x) = 4x - 7; g(x) = x + 3 What is the value of (f circle g)(4)?
looks wrong, lets do it again quick ok
(f o g)(4) f( g(4) ) ^^^
first find g(4) wat do u get ?
How would I do that?
we're given g(x) = x + 3 to find g(4), simply put x = 4 above g(4) = 4+3
(f o g)(4) f( g(4) ) f (4+3) f(7)
find f(7) now give it a try :)
9?
O_o
try again, and do show me wat u tried ok :)
to find g(7), put x = 7 above g(7) = 7+3 And so then 7 + 3 = 10 so g(10)
we're given, f(x) = 4x - 7 so, to find f(7), simply put x = 7 above :- f(7) = 4*7 - 7 = 28 - 7 = 21
Oh, I was way off
10. Use the functions to answer the question. f(x) = 4x – 1; g(x) = 5x2 Which is equal to (f circle g) (x)? (Points : 4)
no, you're doing good, by next question u wil be on track :)
this question u wil be doing urself ok
(f o g)(x) f( g(x) )
plugin g(x) above
(f o g)(x) f( g(x) ) f( 5x2 )
plugin x = 5x2 in f(x)
Okay
(f o g)(x) f( g(x) ) f( 5x2 ) 4*5x^2-1 20x^2 - 1
see if that makes some sense
Alright, it does! I got it. Now, I I got the answer (-5, -8) on this on 3. Use the function to answer the question. f(x) = -3|x + 5| + 8 What is the vertex of the graph of f(x)?
Any Ideas?
f(x) = a|x-h| + k vertex = (h, k)
So 5 and 8
try again
great work helping and explaining @ganeshie8 ^_^
aww ty tester, jonathan is quick learner :) f(x) = -3|x + 5| + 8 = -3|x -(- 5)| + 8
OH!!! Cause you have to take the - sign, so you get.... Wait..... OH!!!! -5 and 8?
yes, you got it !
YAY!!! Lol. 4. Use the function to answer the question. f(x) = |x + 1| What is the range of f(x)? (Points : 4) all real numbers greater than 0 all real numbers greater than or equal to 0 ---> all real numbers greater than or equal to -1 all real numbers greater than -1
hint : range = all y values domain = all x values
f(x) = |x + 1| f(x) = |x + 1| + 0 ^^^
thats the y-coordinate of vertex
So it would be A
try again
Then B?
yes, it includes 0 also cuz vertex will be there at (-1, 0) so range will >= 0
*be
Thank y'all for your help!!!! :D
np :) u wlc !
You want to solve the equation -3 = 5x - 10. That is not the solution to this equation.
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