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x=3y^2
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x=3(y-0)^2+0 is this correct?
the question wants me to know if the graph is parabola and i need to find its vevertex. I followed along the example i had in the book and got this x=3(y-0)^2+0
if it is correct then does that mean y=-2y^2 is x=-2(y-0)^2+0
@Luis_Rivera
@Luigi0210
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x=3y2
|dw:1386699723860:dw|
Yea, it's parabola, but side ways.
thanks man! Been looking for help
so (h,k) must always be (0,0)
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if the equation is short like that
Yup!
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