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Mathematics 6 Online
OpenStudy (anonymous):

x=3y^2

OpenStudy (anonymous):

x=3(y-0)^2+0 is this correct?

OpenStudy (anonymous):

the question wants me to know if the graph is parabola and i need to find its vevertex. I followed along the example i had in the book and got this x=3(y-0)^2+0

OpenStudy (anonymous):

if it is correct then does that mean y=-2y^2 is x=-2(y-0)^2+0

OpenStudy (anonymous):

@Luis_Rivera

OpenStudy (anonymous):

@Luigi0210

OpenStudy (anonymous):

x=3y2

OpenStudy (anonymous):

|dw:1386699723860:dw|

OpenStudy (luigi0210):

Yea, it's parabola, but side ways.

OpenStudy (anonymous):

thanks man! Been looking for help

OpenStudy (anonymous):

so (h,k) must always be (0,0)

OpenStudy (anonymous):

if the equation is short like that

OpenStudy (luigi0210):

Yup!

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