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The Quadratic Polynomial whose zeroes are \(\Large{\frac{3}{5}}\) & \(\Large{\frac{-1}{2}}\) is ???? @AravindG
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(x-a)(x-b)=0 Has its zeros a and b
Use this^
I got \[\Large{\frac{10x^2-x-3}{10}}\] but book says \[\Large{10x^2-x-3}\]
(x-3/2)(x+1/2)=0 (5x-3)(2x+1)=0 10x^2-x-3=0 Yes your book is right!
Infact you are right too...Multiply by 10 on both sides
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Oh 10 is multiplied by '0' on the RHS Thanks Bhaiya :)
yw :)
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