A particle is moving along a line with velocity function v(t)=t^2-t-12feet per second. Find the displacement on the interval 1is less than or equal to t, and t is less than or equal to 5. And the total distance traveled on the interval

Question

amistre64 · Answer

displacement is the integration of velocity along the interval

anonymous · Answer

so do I derive the function

amistre64 · Answer

no, you integrate it

anonymous · Answer

so I plug in 1 and 5 in the equation

amistre64 · Answer

im assuming you know what a derivative or an integral already is ....

amistre64 · Answer

$$\int_{a}^{b}v(t)~dt=displacement$$

amistre64 · Answer

if you know of some other way to define the area underneath the velocity curve, then by all means have at it

anonymous · Answer

okay so I GOT V(T)DT=(T^3/3-T^2/2-12T)

amistre64 · Answer

good, now we evaluate that from t = 1 to 5

amistre64 · Answer

distance im am thinking is the length of that curve, from 1 to 5