Question

Done!

Answer 1

how would you define an altitude geometrically?

Answer 2

this is pretty much the question: find the equation of a line that is perpendicular to a line between 2 other points, and passes thru a stated point.

Answer 3

perp the slope from A to C and anchor it to B, then place it in Ax + By = C format

Answer 4

ignoring that ABC are being used to mean different things of course.

Answer 5

first, find the slope between A and C

next, take the negative reciprocal of that slope for the line.

then use the point slope form of a line to build the equation

then algebra it into standard format

Answer 6

the hardest step is the slope between AC, but even that is fairly simple. How would you go about it?

Answer 7

that is a fine way to go about it :)

we can even use that and just jump to step 2:

-(x2-x1)/(y2-y1) is what we need for a perp slope

Answer 8

reduce it, and take the negative flip of it.

we are wanting to take advantage of the property that perpendicular slopes multiply to -1
\[m_1*m_2=-1\]
therefore:\[m_2=-\frac{1}{m_1}\]

Answer 9

22/-6, flip and negate: -(-6/22), or simply 3/11

Answer 10

now apply this slope, and the point for B for form a line equation with. What do you recall the point slope form to be?

Answer 11

yes, now fill in the parts: m = 3/11, x1=y1=4

Answer 12

y-y1=(3/11)(x-4)
^
4 as well

y - 4 = 3/11 (x-4)

personally, i wold multiply thru by 11, then gather the xy parts to the left and the constants to the right

Answer 13

11y - 44 = 3(x-4)

11y - 44 = 3x - 12

-3x + 11y - 44 = - 12

-3x + 11y = - 12 + 44

and they hate to see a negative in front ... so mutliply thru by -1, or divide by -1, same effect

3x - 11y = 12 - 44

Answer 14

id hope so

Answer 15

cant, have to attend to studies for the finals this week :/

Answer 16

good luck tho :)