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Mathematics 14 Online
OpenStudy (anonymous):

cos2x=0 [0, pi/2]

OpenStudy (anonymous):

cos(2x)=0 ->2x=k*pi +pi/2| KEZ

OpenStudy (anonymous):

x=k*pi/2+pi/4

OpenStudy (anonymous):

what is k

OpenStudy (anonymous):

k is integer ...-1,0,1,2,3,...

OpenStudy (anonymous):

but you have to look wich k is possible in your domain

OpenStudy (anonymous):

rhat is the general formula

OpenStudy (anonymous):

k=0 will lead us to x= pi/4 try othes k's

OpenStudy (anonymous):

i am doing mean value theorem... my derivative is 2cos2x and my value i am setting it equal to is 0 ...so 2cos2x=0 on the interval [0, pi/2]...i got to the point of cos2x=0 so how do i chose a k

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

dont get it

OpenStudy (anonymous):

|dw:1386726416277:dw|

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