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Solve on the interval [0, 2pi) sin3x=0
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\(\sin(3x)=0\) gives a few choices for \(3x\) for example since \(\sin(0)=0\) then \(3x=0\) or \(x=0\) is one solution
another is \(\sin(\pi)=0\) and so \(3x=\pi\) making \(x=\frac{\pi}{3}\)
there are others for example \(\sin(2\pi)=0\) making \(3x=2\pi\) ...
Ah, I understand it now. I can't believe I didn't get it at first. Thank you for helping out!
yeah i figured once you saw it you would see that it is easy. first solve for \(3x\) and then for \(x\) often the \(ax\) throws people off yw
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