Question

1) 2(x - 3) = 2x
- one solution
- no solution
- infinitely many solutions

2) 3(y - 3) = 2y - 9 + y
- one solution
- no solution
- infinitely many solutions

3)10x - 2 - 6x = 3x - 2 + x
- one solution
- no solution
- infinitely many solutions


4. 4(x + 3) + 2x = x -8
- one solution
- no solution
- infinitely many solutions

Answer 1

@charlotte123 @mathstudent55 @jayz657 @rosedewittbukater @Whiterabbit541

Answer 2

well to solve the first one
simplify the expression and see what you get
2(x - 3) = 2x


distributing you get
2x - 6 = 2x

now if you subtract 2x from both sides
you get - 6 = 0

This is a false statement

that means there is no solution for this ok

Try the next one just like this ok

Answer 3

Can you show me how to work the problem ouut...if u can

Answer 4

oo..and thank you.. i just got a 100% on my test

Answer 5

no prob :)
Do you still want an explanation on each problem?

Answer 6

if you want to