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Discrete Math
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Hae friends, will you show that the function y=x^2 is not one to one?
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When x = 1, y = ...?
When x = -1, y = ...?
To show something is one-to-one, you would need to show that f(a) = f(b) if and only if a = b. So basically we're just showing that this is not true. f(a): (a)^2 f(b): (b)^2 a^2 = b^2 square root both sides and you get \[a = \pm b\], which shows the function is not one-to-one.
When x=1,y =1
when x=-1, y=1
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See! You have two different inputs generating the same output!
yes!
By definition, it is not one to one.
Graphically x^2 fails the horizontal line test|dw:1386744459580:dw|. The graph of a one to one MUST only intersect the horizontal line once and only once!
thanks guys!
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