Question

Infinite series,


Can you please help me solve this ? http://screencast.com/t/g88DgTYOvuOY

Answer 1

sorry i can help you out with geometric series only

Answer 2

that's what it is all about

Answer 3

okay i'll give it a try

Answer 4

thanks..

Answer 5

i get a file error from the link

Answer 6

try this one https://www.dropbox.com/s/xqa8f297nrqare6/Screenshot%202013-12-12%2000.01.13.jpg

Answer 7

still bad

Answer 8

http://screencast.com/t/g88DgTYOvuOY

Answer 9

that one took :)

Answer 10

:P

Answer 11

by the p series rule; if |p| < 1, itll converge

Answer 12

so this converges

Answer 13

@amistre ?

Answer 14

@amistre64 ?

Answer 15

i can help you out with question 2 in the first link (b) and (c ) parts
the part b is a decreasing series as the value of n will always be less than e^n as e has an approximate value like 2.something so , n/e^n will always be decreasing
this is not a very good reply but hope you understand something
for the c part, n! will be always less than 3^n so it'll be a decreasing series
like n! will have numbers right from 1,2,3,4,............ to n so there are some small numbers that may reduce (not actually reduce) the value of n!
but there may be a point when n! will be greater thant 3^n so i'm not sure about it
and
for the third link that you have posted, in that for question 3, if you observe it carefully, you'll get that the common difference (p as said by amistre64) is -3/4 whose mod lies between 0 and 1
so it is a decreasing series
hope this helps you and i'm trying other questions

Answer 16

again the fourth is same as the third but here p=2/3 which is +ve but its modulus also lies between 0 and 1

Answer 17

ok thanks!

Answer 18

it's pleasure to help somebody and thanks for the medal

Answer 19

for question 5 in the first link, i don't know the S2^n rule but by logical reasoning , we cansay that the harmonic progression is decreasing as the numerator is constant i.e. 1 and the denominator is increasing with the value of n so we can say that it is a decreasing series

Answer 20

i'll have to go now as it's 4:00 in the morning in my country and i haven't slept all night sorry but 'll surely help you when i' back
once again i'm sorry-_-