Solve In2+ In x=5
Mind checking your textbook or notes for the 3 "rules of logs"? The first one is: (1) ln a + ln b = ln a*b (the log of a product (example: a*b) is the sum of the logs of the multiplicands a and b (example: ln a + ln b. So ln (a*b) = ln a + ln b. (2) (3) Now apply Rule (1) to ln 2 + ln x = 5. Combine the 2 separate logarithmic terms into one. You'll get the logarithmic equation ln ( ?? ) = 5. Which property of logarithmic and exponential functions could you then use to solve for x?
I have no idea.
Have you your textbook and/or class notes available? If so, have you looked up any of the material that deals with logarithmic equations and the inverse function relationship of y = ln x and y = e^x? You will need to know this material. Please start by asking questions, even very basic ones; then you'd be more in control of your own learning.
I just want the answer. Thats all. I need help.
Well, um, uh, uh. The correct rule of logs to apply here is ln a + ln b = ln a*b. In words, the logarithm of a product, a*b, is equal to the SUM of the logs of the two factors. So: ln a + ln b = ln a*b ln 2 + ln 5 = ln (2*5) = ln (?)
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