Question

How do i find the vertex of this ?
x^2 = 12y

Answer 1

is it just
(0,0) ?

Answer 2

shamil is right. The vertex is (0,0).
If its vertex were not at the origin, it would look something like this:
(x-3)^2 = 12(y+1)
where the -3 and 1 would mean the vertex moves 3 units to the right and one unit down. (Of course, those two numbers I added are just examples; they could really be any two numbers.)

Answer 3

alright thanks

Answer 4

You're welcome!