Question

ln(1-x)+ln(3-x)=ln8

Answer 1

Whatever you do to one side, you do to the other.
How do you get rid of any ln's?

Answer 2

\(\ln(a) + \ln(b) = \ln(ab)\)

Answer 3

so:
\[\ln((1-x)(3-x))=\ln(8)\]

Answer 4

so:
\[\ln(x^2-4x+3)=\ln(8)\]
or:
\[x^2-4x+3-8=0\]
\[x^2-4x-11=0\]
now use the quadratic formula so you get:
\[2 \pm \sqrt{15}\]