Question

Whats the radius of the equation: (x-2)^2 + y^2 = 14

Answer 1

The general equation of a circle (x-h)^2 + (y-k)^2 = r^2
where (h,k) is the center of the circle and r is the radius.
Compare (x-2)^2 + y^2 = 14 to the above and you can quickly find the radius r.

Answer 2

I dont know how to convert it into general form.

Answer 3

You don't have to convert it. They have already given you the equation in general form. You simply have to compare them:

(x-h)^2 + (y-k)^2 = r^2
(x-2)^2 + (y-0)^2 = 14

You can see that r^2 = 14. Therefore the radius r is sqrt(14).