Question

What is the solution to the equation?

√2x+10 -6=2

Answer 1

Is it this:
\[\sqrt{2x} + 10 - 6 = 2\]
\[\sqrt{2x + 10} - 6 = 2\]
Or
\[\sqrt{2x + 10 -6}\]
?

Answer 2

sorry, add =2 at the end of the third option

Answer 3

the second one, its fine (:

Answer 4

Okay, so first, move the 6 to the other side.
\[\sqrt{2x + 10}=2+6\]
\[\sqrt{2x + 10}=10\]
Now what?

Answer 5

next divide?

Answer 6

nope. Next, get rid of the square root. Do you know how to do that?

Answer 7

No.. ;-;

Answer 8

Well let's see. What's the opposite of taking the SQUARE root of a number? The power of two, or SQUAREing a number.
So how would you cancel the square root? By squaring it.
\[(\sqrt{2x + 10})^{2} =10^{2}\]

Answer 9

what next?

Answer 10

multiplying?

Answer 11

multiply 10^2 which would make it 100. right?

Answer 12

Assuming that it is indeed the third option.\[\sqrt{2x+10-6}=2\]\[\sqrt{2x+4}=2\]2x+4=4
x=0
You did not really mean it was the third option, did you?

Answer 13

It is so important to clearly represent the problem.

Answer 14

\[\sqrt{2x+10} -6=2\]

Answer 15

Sorry, I read the StudyGurl14 post and thought it was yours.
\[\sqrt{2x+10}=8\]\[2x+10 = 64\]After squaring both sides.
2x=54 after subtracting 10 from both sides
x=27 after dividing both sides by 2

Answer 16

Do you have that (x=27) as a possible solution?

Answer 17

Good luck with these. One thing to be aware of, when a radical is squared there is a possibility of losing a sign.

Answer 18

oh stupid me. I did 2 + 6 as 10, not 8

Answer 19

sometimes I don't know where my mind is

Answer 20

Anything but stupid, call it a typo, or a momentary lapse. You deserve a medal.

Answer 21

Thanks. Did you get the answer?

Answer 22

The "Did you get the answer?" was directed to @akwardpanda. The Thanks was directed to @radar.

Answer 23

Yes I did (: thank you both.