Find the equation for a parabola with the vertex of -3,0.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[(x+3)^2\]
OpenStudy (anonymous):
what about a parabola with the vertex 0,0
OpenStudy (anonymous):
\[x^2\]
OpenStudy (anonymous):
umm 3,0
OpenStudy (anonymous):
\[(x-3)\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
0,-2
OpenStudy (anonymous):
\[y=a(x-h)^2+k\] is the form for any parabola where a is the slope/direction, and (h,k) is the vertex.
OpenStudy (anonymous):
yeah i know but i dont understand how to work them out thats why im asking for help
OpenStudy (anonymous):
Well if you want something to be moved along the x axis, then change h. So for the first you wanted x to be -3 so you have to make -h=-3, so h=3. For the second, you wanted both x and y to be 0, so we made h and k both equal to 0.
OpenStudy (anonymous):
LOL yeah it is still confusing to me.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
okay so i tried to workout the 0,-2 question. what answer did you get? and i will see if i got it right. please
OpenStudy (anonymous):
Great, what did you get?
OpenStudy (anonymous):
Never mind it is wrong. The way I did it makes no since at all.