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How many solutions are there to the following system of equations? 4x-14y=6 -2x+7y=-3 0 1 2 infinitely many
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Note that \(\large 4x-14y = 6 \implies -2(-2x+7y) = -2(-3) \implies -2x+7y = -3\). With that said, can you figure out how many solutions you have now? :-)
Two equations are constant multiple of each other. In order to solve for two variables x and y you need two unique equations.
It have 0 Solutions since both the equations are same :)
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Since the system of equations reduces to one line \(\large -2x+7y = -3\), then there are an infinite number of solutions because there are an infinite number of points \(\large x,y\) that lie on tje line. Does this clarify things? :-)
yes thank you.
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