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2(-4)^2-2(2)^4+3^2-(-4)^2+2^4
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\[2(-4)^{2} - 2(2)^{4} + 3^{2} -(-4)^{2} + 2^{4}\] right?
yes
Okay, so order of operations. What do you do first?
your exponents
Yes. Just od them one at a time. \[(-4)^{2}\] What is that equal to?
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-16
No. When the negative is in parenthesis, the square is possite. so the answer would be 16
Now \[(2)^{4}\] What is this?
when i did this problem i got -7 is that right?
No. The next one: \[3^{2}\]
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PS: What is 2 to the 4th power
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