Write a coordinate proof. If a quadrilateral is a kite, then its diagonals are perpendicular.
@hartnn
Someone please help. This is my last question and I've been working on this for 2 days.
@ayeeturnup
dang im sorry thats harddd
yeah... I've been stuck on it forever and I keep like messaging people and asking them for help but nobody will help...
@hartnn @ganeshie8 can one of you please help me!?
ok so we want to prove that if a quadilateral is a kite, then its diagonals are perpindicular. so we can assume this quadrilateral is a kite. thats the first thing we would do. assume that is given
Okay and then what?
whats the definition of a kite, we will need that
i think in a kite, the two adjacent sides are congruent
A 4-sided flat shape with straight sides that: * has two pairs of sides. * each pair is adjacent sides (they meet) that are equal in length. Also, the angles are equal where the pairs meet. Diagonals meet at a right angle, and one of the diagonal bisects the other.
@amistre64
lets use this as a template http://www.algebra.com/algebra/homework/Geometry_proofs.faq.question.555730.html
we can substitute what you have in your drawing
Okay can you show me?
sure
well a coordinate proof is a little different than a geometry proof, since we use coordinates
it would be easier i think to prove it without coordinates,
nah, just show that the slopes of the lines that create the diagonals are perp
ahh, yes that would work
but you have to do it based on whats given
oh nevermind
i was thinking geometry :D
2 points define a slope :) but you might have to use the idea that 1/0 is perp to 0/1
so it looks the proof is 1 line
use pythag thrm otherwise
just use slope formula and youre done?
Okay thanks guys. I get it now. since one slope is undefined and the other is 0 they are perpendicular
ok , slope of diagonal XZ = (b-b)/(2a-0) slope of diagonal WY = (4b-0)/(a-a) too easy
correct, as long as you are above to use that definition, then its pretty easy to show
but this doesnt prove that all kites have diagonals that are perpindicular
this only proves that the given figure has diagonals perpindicular
the given is a kite;
it says if its a kite, then ______ we have a kite, show that its perped
the statement reads "if a quadrilateral is a kite, then the diagonals are perpindicular". this is a special case of a kite, draw in the figure
the figure is a generality of a kite, which is why there are no specific point values
well i think a proper proof would say that any kite can be drawn like this.
All kites can be construced as WXYZ, the ab parts make it so that you can define ANY kite by this general construction
i dont see anywhere in the directions where it says this figure is a kite. what i would do first is show that it is a kite, by proving the adjcent sides are congruent
so you can use pythagorean theorem, to show that WZ = WX , and the other two sides are congruent.
the hypothesis does not have to be demonstrated. It only has to be generalized to fit ANY construction that matches the definition of a kite.
and the last step can be, since any kite can be drawn like the kite in the diagram (by rotation, scaling, whatever), and since we proved the slopes are perpindicular, then we are done
right, but what if you drew a non-kite and then proved its diagonals are perpindicular (which happened to be a coincidence). i mean, its good to just check that it is in fact a kite.
for me the proof to be persuasive is that the figure is actually a kite. i dont trust somebody just drawing something freehand
and then say, oh my freehand drawn kite has diagonals perpindicular.
if p then q = -p v q p -p q -pvq 0 1 0 1 0 1 1 1 1 0 0 0 1 0 1 1 <-- this setup is what we are going for. if p is false, then q is true regardless we are assuming that p is given, and is true show that q is true to verify the statement or show that q is false to contradict the statement
but its pretty easy to check by pythagorean that the sides are congruent. im just saying that it is a good step. even if the directions say, this figure is given as a kite, I think the coordinates of the kite should reflect that. what if there was a typo in the figure, you know. its just one extra step.
lol, um, if p is false, then the statement is true regardless of q is what i should have said ...
right, but then you are not proving the claim that all kites have perpindicular diagonals. since you did not draw a proper kite in the first place
im not opposed to verifying the kiteness of it :)
my point is, if they happened to draw a non kite, then you didnt prove the claim that all kites have perpindicular diagonals, even if the figure turned out to have perpindicular diagonals (or not).
i understand that we want to look only at kites, since it is trivially true for non kites. thats my point. how do we know its a kite. you say its given, ok, let me check the coordinates on this 'given' kite
i guess what im saying is, if you wanted to prove this from scratch, then you should justify that your given kite is really a kite, since we are using coordinates.
ok consider this scenario. Suppose you wanted to do a proof from scratch let say, and by accident you draw a non kite on the coordinate plane and then by coincidence the diagonals are perpindicular. and you think you have proven the claim.
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