find the slope: A. (-2,6), (-4, -7) B. y = (1/4)x + 2 C. (-4,-4), (-7, 24) HELP!!!!!!!!!!
To find the slope using just cordinates you use this: \[\frac{ y ^{1}-y ^{2} }{ x ^{1}-x ^{2} }\]
So, to do A and C you would start out with your coordinates (I will use A) and input them in the equation. If you do that then your equation should be this: \[\frac{ 6-(-7) }{ -2-(-4) }\]
Subtracting a negative = adding a positive, so it would be: \[\frac{ 6+7 }{ -2+4 }\]
Once you solve that, then that is your slope. I hope you'd know how to solve that. Just add the 6 and 7, and the -2 and 4. Then divide it. so 13 divided by 2, which is 6.5. That's your slope.
For one like B, it's already in equation form, slope intercept form. Your slope is: y=mx+b. x= x intercept b= y intercept m= slope. Using that information what do you think the slope is?
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