@Ammarah
\(\large (256)^{\frac{3}{4}}\) \(\large (4^4)^{\frac{3}{4}}\) \(\large (4^3)\) \(64\)
did u power it to 4 cus 4^4=256?
yes ! check it urself 4*4*4*4 = ?
256
256 = 4*4*4*4 = 4^4
easy ok. just u need to write the inside thing 256 as useful powers of something so that u can cancel the radical exponent.
alright can u give me another prob to solve? i have a test tomm and i need to study
simplify : \(\large 16^{\frac{1}{4}}\)
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yes, but u dont have to change it to radical form. simply write 16 as 2^4, and cancel the fractional exponent
wait can u draw itout
\(\large (16)^{\frac{1}{4}} \) \(\large (2^4)^{\frac{1}{4}} \) \(2\)
ok
il give one more problem to simplify
simplify : \(\large 32^{\frac{1}{2}}\)
2?
try again
idk...
\(\large (32)^{\frac{1}{2}} \) \(\large (2\times 16)^{\frac{1}{2}} \) \(\large (2\times 4^2)^{\frac{1}{2}} \) \(\large (2)^{\frac{1}{2}} \times (4^2)^{\frac{1}{2}} \) \(\large (2)^{\frac{1}{2}} \times 4\) \(\large \sqrt{2} \times 4\) \(\large 4\sqrt{2} \)
ok how much onger r u on??? cuz if any questions conme up ill ask u
il be around :) its afternoon time here in india...
ooh u live in india!! my grandparents r from there
yeah i guessed that, Amar is an indian name lol. it means 'lives forever'
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