Question

Will give medal. What are the domain and range of the following function:
f(x)=x^2-2x+2

Answer 1

@satellite73

Answer 2

it is a polynomial, so domain is all real numbers

Answer 3

because the graph is a parabola that opens up, the range will be from the second coordinate of the vertex to infinity, so you need to find the vertex

Answer 4

the first coordinate of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\)
you have \(f(x)=x^2-2x+2\) so the first coordinate of the vertex is \(-\frac{-2}{2\times 1}=1\)

Answer 5

the second coordinate of the vertex is \(f(1)\) compute that number

Answer 6

will it be domain=all real numbers, and range equal y>=1

Answer 7

yes

Answer 8

Ok. Thank you. I've been trying to figure that out for awhile now. :)

Answer 9

yw