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Will give medal. What are the domain and range of the following function: f(x)=x^2-2x+2
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@satellite73
it is a polynomial, so domain is all real numbers
because the graph is a parabola that opens up, the range will be from the second coordinate of the vertex to infinity, so you need to find the vertex
the first coordinate of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\) you have \(f(x)=x^2-2x+2\) so the first coordinate of the vertex is \(-\frac{-2}{2\times 1}=1\)
the second coordinate of the vertex is \(f(1)\) compute that number
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will it be domain=all real numbers, and range equal y>=1
yes
Ok. Thank you. I've been trying to figure that out for awhile now. :)
yw
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