Question

Solve, using the substitution method.

y – 2x = 8
16 + 4x = 2y

Answer 1

First equation, solve for y. y=2x+8. Then in the second equation, substitute in 2x+8 when you see a y.

Answer 2

Let's get y by itself on the first equation.

y = 8 +2x

Now we substitute y in the second equation, which is 8+2x
16 + 4x = 2(8+2x)
16 + 4x = 16 + 4x

Looks like it ends up cancelling both sides, so x = 0
Now we plug in 0 for x to solve for y

y = 8 + 2(0)
y = 8

Let's double check.

8 - 0 = 8 (Confirmed first equation)
16 - 0 = 2*8 (Confirmed second)

Answer 3

16+4x=2(2x+8) then solve the equation for x

Answer 4

Soo the solution is what?

Answer 5

Solution is y=8 and x=0

Answer 6

I don't think so. you get 16+4x=4x+16 everything cancels out so you get 0=0.
I believe the solution is all real numbers

Answer 7

16+4x-4x=4x+4x+16
16=16

or 16-16+4x-4x=4x-4x+16-16
0=0

Answer 8

My options are the solution is (24,0), the solution is (1,10), there is no solution, and There are an infinite number of solutions

Answer 9

My bad, it's infinite number of solutions as DSS said.

Answer 10

Thanks G-unit and DSS!!!