Question

A parallelogram has the vertices (0, 3), (3, 0), (0, -3) and (-3, 0). Find the perimeter and area

Answer 1

Use the pythagorean theorem to determine the length of each side
a=3, b=3 so \[3^{2}+3^{2}=c ^{2}\]
c^2=18
\[c=\sqrt{18} or 3\sqrt{2}\]

Answer 2

for perimeter you add s+s+s+s
area s*s

Answer 3

\[P=3\sqrt{2}+3\sqrt{2}+3\sqrt{2}+3\sqrt{2}=12\sqrt{2} units\]
\[A=3\sqrt{2}(3\sqrt{2})=9*2=18 sq units\]

Answer 4

thank you so much!