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Mathematics 18 Online
OpenStudy (anonymous):

Which of the following is not a perfect square trinomial?

OpenStudy (anonymous):

jigglypuff314 (jigglypuff314):

perfect square trinomials are in the form of: a^2 + 2ab + b^2

OpenStudy (jdoe0001):

change the 1st term on each choice to the SQUARED version of it then factor the middle term by 2, then recheck the choices

OpenStudy (anonymous):

What do you mean by factor the middle term by 2 ?

OpenStudy (jdoe0001):

\(\begin{array}{llll} 144+12y+y^2\implies &12^2+2(6)y+y^2\\ 100+20y+y^2\implies &10^2+2(5)y+y^2\\ 64-16y+y^2\implies &8^2-2(8)y+y^2\\ 25+10y+y^2\implies &5^2+2(5)y+y^2 \end{array}\) so... which one do you think?

OpenStudy (jdoe0001):

like so

jigglypuff314 (jigglypuff314):

so like for 100 + 20y + y^2 100 = 10^2 so the middle should consist of 2*10*y = 20y therefore option B IS a perfect square trinomial

OpenStudy (jdoe0001):

hm... I got the ... olemme fix that

OpenStudy (jdoe0001):

\(\begin{array}{llll} 144+12y+y^2\implies &12^2+2(6)y+y^2\\ 100+20y+y^2\implies &10^2+2(10)y+y^2\\ 64-16y+y^2\implies &8^2-2(8)y+y^2\\ 25+10y+y^2\implies &5^2+2(5)y+y^2 \end{array}\) there, now recheck the choices... what do you think?

OpenStudy (anonymous):

I have to look for an error right ?

jigglypuff314 (jigglypuff314):

yep :) one that did not fit into the pattern of a^2 + 2ab + b^2

OpenStudy (jdoe0001):

hmm... recall, as jigglypuff314 already pointed out, the middle term in a perfect square trinomial, is the multiplication of 2 * 1st term (non-squared), * 2nd term (non-squared)

OpenStudy (anonymous):

Is it D ?

OpenStudy (jdoe0001):

\(\bf (a+b)^2\implies a^2+2ab+b^2\qquad \qquad (a-b)^2\implies a^2-2ab+b^2\)

OpenStudy (jdoe0001):

well, let's see D closely \(\huge 25+10y+y^2\implies 5^2+2(5)y+y^2\) is it not a perfect square trinomial?

OpenStudy (anonymous):

It is !?

OpenStudy (anonymous):

So the answer is C then....

OpenStudy (jdoe0001):

\(\large 25+10y+y^2\implies \color{red}{5}^2+2(\color{red}{5})\color{red}{y}+\color{red}{y}^2\)

OpenStudy (jdoe0001):

if you grab the 1st term, non-squared and 2nd term, non-squared, it should give you the middle term if multiplied by 2

OpenStudy (anonymous):

I think I got it now, its A right ?

jigglypuff314 (jigglypuff314):

correct :)

OpenStudy (anonymous):

Thank you soooooo much guys !!

OpenStudy (jdoe0001):

yw

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