Tonight is the end of the semester and I need a little help! I'm not sure how to do anything with Linear Equations and Inequalities. I've tried to learn this many times but I don't understand any of it. Can someone please help me out?

Question

anonymous · Answer

study your textbook always helps. Works fine for me

anonymous · Answer

I've tried I just don't understand it.

anonymous · Answer

try to internet. Youtube is good

anonymous · Answer

I have. I just need a one-on-one with someone teaching me.

phi · Answer

you could post a question that you would like to know how to solve

anonymous · Answer

I don't have any particular questions. I basically just need to know how to solve and/or graph them.

phi · Answer

example ?

phi · Answer

I can only guess what you are studying. maybe this http://www.khanacademy.org/math/trigonometry/systems_eq_ineq/systems_inequalities_precalc/v/graphical-system-of-inequalities ?

anonymous · Answer

Yes!

anonymous · Answer

And slopes. For example: Find the slope of the line assing through the points (-3, 7) and (1, 2).

anonymous · Answer

passing*

phi · Answer

search Khan's site for anything you might want to review. He has lots on slope. For example http://www.khanacademy.org/math/algebra/linear-equations-and-inequalitie/slope-and-intercepts/v/slope-of-a-line-2

anonymous · Answer

A linear equation is one with the variables having no power other than 1, such as x and y.

If something, y, grows proportional to x, such as y=mx, that is a simple linear equation. If y is not 0 but b when x = 0, we get the general form of a straight line:

y=mx + b.

The repairman charges $50 per hour (h) and $25 for showing up at all:

Cost = ($50/hr)(h) + $25. A two-hour job (h=2) will cost you $125.

If you have two such lines

y1 = m1 x + b1

y2 = m2 x + b2,

they will intersect somewhere unless parallel (m1=m2, same slopes)

To "solve" that pair of equations is to find where they 

meet  

x = (b2 - b1)/(m1-m2) 

where you know all these values but x.  

y is obtained by substituting this x into one of your equations, y1 or y2.

There are lots of other interesting aspects, but these are often most useful.