4. Complete this statement: The sum of the measures of the exterior angles of an n-gon one at each vertex, is ____ degrees. (1 point) 360 (n-2) 180 (n-2) 180/n 180n
|dw:1386998321815:dw|
Consider an octagon first.
|dw:1386998381724:dw| This inner angle is just \(360^\circ /8\)
The outer angles must add to it to be \(180^\circ\) since it is a triangle. Thus the sum of the outer angles is \(180^\circ - 360^\circ / 8\)
|dw:1386998481902:dw|
There are \(8\) of them, so the sum of exterior angles will be \[ 8\times \left(180^\circ - \frac{360^\circ }{8}\right) \]
Change \(8\) to \(n\): \[ n\left(180^\circ - \frac{360^\circ }{n}\right) = 180^\circ n-360^\circ = 180^\circ n-180^\circ (2) = 180^\circ (n-2) \]
So the sum of the exterior angles is \(180^\circ (n-2)\) and each exterior angle is \(180^\circ (n-2)/n\)
so its c?
What is the question asking for?
its asking for the degrees of the vertex at each angle
@baddiemaddie >>>> so its c? No. The sum of the measures of the exterior angles of an n-gon one at each vertex, is ____ degrees. Polygon Exterior Angle Sum Theorem Read the first sentence here: http://hotmath.com/hotmath_help/topics/polygon-exterior-angle-sum-theorem.html
@baddiemaddie Do you see the answer?
Yes thanks!
That's good news.
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