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Mathematics 21 Online
OpenStudy (anonymous):

4. Complete this statement: The sum of the measures of the exterior angles of an n-gon one at each vertex, is ____ degrees. (1 point) 360 (n-2) 180 (n-2) 180/n 180n

OpenStudy (anonymous):

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OpenStudy (anonymous):

Consider an octagon first.

OpenStudy (anonymous):

|dw:1386998381724:dw| This inner angle is just \(360^\circ /8\)

OpenStudy (anonymous):

The outer angles must add to it to be \(180^\circ\) since it is a triangle. Thus the sum of the outer angles is \(180^\circ - 360^\circ / 8\)

OpenStudy (anonymous):

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OpenStudy (anonymous):

There are \(8\) of them, so the sum of exterior angles will be \[ 8\times \left(180^\circ - \frac{360^\circ }{8}\right) \]

OpenStudy (anonymous):

Change \(8\) to \(n\): \[ n\left(180^\circ - \frac{360^\circ }{n}\right) = 180^\circ n-360^\circ = 180^\circ n-180^\circ (2) = 180^\circ (n-2) \]

OpenStudy (anonymous):

So the sum of the exterior angles is \(180^\circ (n-2)\) and each exterior angle is \(180^\circ (n-2)/n\)

OpenStudy (anonymous):

so its c?

OpenStudy (anonymous):

What is the question asking for?

OpenStudy (anonymous):

its asking for the degrees of the vertex at each angle

Directrix (directrix):

@baddiemaddie >>>> so its c? No. The sum of the measures of the exterior angles of an n-gon one at each vertex, is ____ degrees. Polygon Exterior Angle Sum Theorem Read the first sentence here: http://hotmath.com/hotmath_help/topics/polygon-exterior-angle-sum-theorem.html

Directrix (directrix):

@baddiemaddie Do you see the answer?

OpenStudy (anonymous):

Yes thanks!

Directrix (directrix):

That's good news.

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