A restaurant has one type of lemonade that is 12% sugar and another that is 7% sugar. How many gallons of each type does the restaurant need to make 20 gallons of a lemonade mixture that is 10% sugar? A) 12 gallons of the 12% lemonade and 8 gallons of the 7% lemonade B) 10 gallons of the 12% lemonade and 10 gallons of the 7% lemonade C) 8 gallons of the 12% lemonade and 12 gallons of the 7% lemonade D) 2 gallons of the 12% lemonade and 18 gallons of the 7% lemonade
no idea
@Luigi0210 can you help me please? (:
@hartnn I need help once again lol
I kind of have to leave soon, but I think hartnn can figure it out c:
okay!
let x be the number of gallons of 12% sugar lemonade y = number of gallons of 7% sugar lemonade since we need 20 gallons of a lemonade mixture that is 10% sugar, we first have x+y =20 got this ?
so x + y = 20 12 + 7
nevermind 12 and 7 are the percentages not gallons
ok, we need one more equation, 12% of sugar x = 0.12 x 7% of sugar y = 0.07y this should equal, 10% of sugar in 20 gallons mixture which is 0.10*20 so we have 0.12x+0.07y = 0.10*20 see if u get this...
yes I get it
now you have 2 equations, 2 unknowns, can you solve for x and y ? x+y =20 0.12x+0.07y = 0.10*20
am I supposed to put it in slope intercept form to solve for x and y?
you can start by using substitution method from 1st equation y = 20 -x substitute this 'y' in 2nd equation 0.12x +0.07(20-x) = 2 can u get x from this?
okay.. I got 0.12x + 1.4 = 2
what about the 0.07*(-x) term ?
would I subtract 1.4 - 0.12 to get x?
0.12x +0.07(20-x) = 2 0.12x + 0.07 * 20 - 0.07*x = 2 0.12x + 1.4 - 0.07x = 2
x (0.12 -0.07) = 2-1.4
x(0.05) = 0.6 x= 0.6/ 0.05 = 60/5 = 12
go through these steps and tell me if you have any doubt in any step
so the answer would be A?
YES.
lol im sorry math is my worst subject.. it takes me awhile to get it :/
no problem, glad you got it :)
Thank you! (:
welcome ^_^
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