Question

Anyone know how to do this?

Answer 1

http://www.wolframalpha.com/input/?i=y%3De%5E%7B2x%7D%2Fx

Answer 2

it doesn't tell me how to do it

Answer 3

Do you know how todo any portions of it?

Answer 4

not really

Answer 5

Vertical asymptotes are at x-values that make the function undefined.

Answer 6

Are we okay with getting that part of it?

Answer 7

yea

Answer 8

For horizontal asymptotes, we want to test the limit as x goes to infinity and as x goes to negative infinity.

Answer 9

ok

Answer 10

Lemme know when ya got that.

Answer 11

yea i got it but i dont understand the part where it says the graph of g(x)

Answer 12

Ah. What did you find for all the asymptotes sofar then?

Answer 13

that the part I dont understand how to do, Do i just plug infinity to the x in the equation?

Answer 14

Right. You havent seen l'hopitals rule by chance, have you?

Answer 15

is it when you find the derivative of both the top and bottom?

Answer 16

Yeah, exactly. So if you were to do l'hopitals rule. you would get 2e^(2x). Then you would plug in infinity and negative infinity.



Because of the basic graph of an e^x function, plugging in x to infinity would just give a limit to infinity. But plugging in negative infinity takes the limit to 0, simply based on the graph of e^x. So according to the functions limits, there is a horizontal asymptote at y = 0 when going towards negative infinity, but no horizontal asymptote going to infinity.