Question

q

Answer 1

q attached below !

Answer 2

@robtobey

Answer 3

@amistre64

Answer 4

@e.mccormick

Answer 5

i would imagine this to be a right triangle problem, but i cant see anything that would verify my assumption.

im thinking law of cosines, since its a more general setup ... the pythag thrm being a special case

Answer 6

how to do that ?

Answer 7

can u draw the figure plz ?

Answer 8

dunno, its just an idea at the moment ...

Answer 9

can u explain ur figure

Answer 10

500^2 = r^2 + s^2 -2sr cos(30)

the figure is an airplane taking off at an airport id assume.

Answer 11

so u have used law of cosines !

Answer 12

i have tried to apply it, since I cannot determine from the information presented if it is a right triangle or not.

Answer 13

ok

Answer 14

it should hopefully give us some sort or relationships to play with.

500^2 = r^2 + s^2 -2sr cos(30)

taking an implicit derivative

0 = 2r r' + 2s s' -2s'r cos(30) -2r's cos(30)

0 = r r' + s s' -s'r cos(30) -r's cos(30)

r' = 140, determine s'

0 = 140r + s'(s -r cos(30)) -140s cos(30)

140s cos(30) - 140r = s'(s -r cos(30))


140s cos(30) - 140r
------------------ = s'
s -r cos(30)

we would need to find a way to determine the values of s and r ...

Answer 15

if we can assume a 30-60-90