Find the critcal points and using the second derivative test determine if local max/min exists or if the test is inconclusive. x^4/2-12x^2
\[\huge \frac{ x^4 }{ 2 } - 12x^2\] is this your problem?
When i took both derivatives i got,\[f \prime = 2x^3-24\] and \[f \prime \prime\] = 6x^2-24\]
^^yes
nvm, you made a typo lol
I factored out the first derivative to get, \[2x(x^2-12)=0\]. Then i plugged in my points , -4,-1,2,and 4 in the 2nd derivative to get, a local max at -4, -1 and local min at 2, and 4
oh i forgot my critical points are \[x=0,\sqrt{12}\]
yeah, mb , i was looking at the second derivative for a sec, you're right with the critical points
so i just want to make sure that when i'm solving these, I must always factor out the first derivative not the second one correct?
yeah, i made mistake looking at the second derivative, the critical points are found by taking the first derivative and seeing which values of x make the derivative zero
oh ok
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