Paul teaches the guitar in groups of three students. He rents a room for the guitar classes at $250 per month. He charges $30 per hour per student. Paul teaches six groups of students, and his net earnings per month are $1,910.
Part A: If each student learns guitar for the same number of hours, write an equation that can be used to calculate the number of hours each student learns guitar in a month.
Part B: How many hours did each student learn guitar each month? Show your work and justify each step of your work.
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OpenStudy (anonymous):
@agent0smith
OpenStudy (anonymous):
@skullpatrol
OpenStudy (anonymous):
30x+250=1910 i do not think what i have is right for part a
OpenStudy (agent0smith):
He rents the room for $250. That means he PAYS 250, he doesn't make 250.
OpenStudy (anonymous):
o ok
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OpenStudy (anonymous):
what would be the equation
OpenStudy (agent0smith):
Paul teaches the guitar in groups of three students. Paul teaches six groups of students,
How many students must there be, from these two sentences?
OpenStudy (anonymous):
3?
OpenStudy (agent0smith):
Read it again.
OpenStudy (anonymous):
6 groups
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OpenStudy (anonymous):
ooh... wait
OpenStudy (anonymous):
18
OpenStudy (agent0smith):
Yes. Now try writing the equation if x is the number of hours a student gets. You had it pretty close above.
OpenStudy (anonymous):
ok.....
OpenStudy (anonymous):
18(30)-250=1910?
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OpenStudy (agent0smith):
18 students, 30 an hour per student, with x number of hours means 18*30*x
OpenStudy (agent0smith):
But close!
OpenStudy (anonymous):
18*30*x?
OpenStudy (anonymous):
540x?
OpenStudy (agent0smith):
All you have to do is modify your above equation, you almost had it.
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OpenStudy (anonymous):
540x+250=1910
OpenStudy (anonymous):
?
OpenStudy (agent0smith):
But... I thought we went over him paying 250, not making 250
OpenStudy (anonymous):
but dont you need to add it so then you can subtract it when solving?
OpenStudy (anonymous):
u know inverse operations?
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OpenStudy (anonymous):
can we go to part b @agent0smith
OpenStudy (agent0smith):
It's nothing to do with inverse operations. He PROFITS 540x, he loses 250, the way you wrote it he's not paying 250 for the room, he's making 250.
OpenStudy (anonymous):
540x-250=1910
OpenStudy (anonymous):
it makes sense
OpenStudy (agent0smith):
Better, now solve it.
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OpenStudy (anonymous):
290x=1910
OpenStudy (anonymous):
x=about 6
OpenStudy (anonymous):
?
OpenStudy (agent0smith):
You can't combine unlike terms like that. You can't combine an x term like 540x, with a constant term like -250
OpenStudy (anonymous):
how do you solve then
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OpenStudy (anonymous):
@agent0smith
OpenStudy (anonymous):
?
OpenStudy (anonymous):
okay the total answer i got was x=3
OpenStudy (agent0smith):
540x-250=1910
add 250 to both sides
OpenStudy (anonymous):
okay..... you get 540x=2160
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OpenStudy (anonymous):
x=4
OpenStudy (anonymous):
i think i am getting the hang of it...... is it right?
OpenStudy (anonymous):
1910 is the NET cost
OpenStudy (anonymous):
that includes 250
OpenStudy (anonymous):
so it would be 540x+250=1910 or 540x-250=1910
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OpenStudy (anonymous):
@agent0smith
OpenStudy (agent0smith):
"and his net earnings per month are $1,910"
OpenStudy (agent0smith):
Net earnings are the money he makes overall, after paying for the room.
OpenStudy (anonymous):
yeah so it would be 540x+250=1910
OpenStudy (anonymous):
this is craziness!
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OpenStudy (agent0smith):
He MAKES money off his students. He LOSES money to the room, meaning you must subtract it.
OpenStudy (anonymous):
oooooooh he LOSES
OpenStudy (agent0smith):
It's not craziness. We already went over it, you had everything correct.