Need help What is the solution of the equation?

Question

anonymous · Answer

attachment

anonymous · Answer

A.26
B 2 THATS WRONG
C.38
D.14

anonymous · Answer

you mean you have options? it doesn't occur to you to put them in the calculator?

anonymous · Answer

I don't have one

anonymous · Answer

___
x ^2 =2|dw:1387067741435:dw|/   x

anonymous · Answer

which one is that

anonymous · Answer

its not an option it is rather a rule

anonymous · Answer

I put 2 but I got it wrong

anonymous · Answer

the answer is A. 26

anonymous · Answer

Can you tell me why

anonymous · Answer

first u subtract 3 from both sides. then u divide both sides by 2. then you multiple both sides to the power of 5. then u cube root both sides. you now have x+6=32. so x=26

anonymous · Answer

ok thanks you a lot do you think you v\can help me some more

anonymous · Answer

sure :)

anonymous · Answer

What is the simplest form of the expression?

anonymous · Answer

sorry jasmine idk about that one

anonymous · Answer

ok an @kc_kennylau what do you mean

mertsj · Answer

1.  Subtract 3 from both sides.
2.  Divide both sides by 2
3.  Raise both sides to the 5th power
4.  Take the third root of both sides
5.  Subtract 6 from both sides.
6.  You are done.

anonymous · Answer

which one s this for the 1st or 2nd one an I don't have a calculator

kc_kennylau · Answer

$$\large\frac{\sqrt{6x^8y^9}}{\sqrt{5x^2y^4}}=\sqrt{\frac{6x^8y^9}{5x^2y^4}}$$This should help you :)

anonymous · Answer

attachment

kc_kennylau · Answer

don't ask us to give you the answer and have a look at my welcome msg although you aren't new: Welcome to OpenStudy :D You may want to read the code of conduct ( http://openstudy.com/code-of-conduct ). Don't forget to click on the button called "Best Answer" to give a medal to the person who helped you :)

kc_kennylau · Answer

$$\Large\frac{\sqrt{6x^8y^9}}{\sqrt{5x^2y^4}}=\sqrt{\frac{6x^8y^9}{5x^2y^4}}=\frac{\sqrt{30x^6y^5}}5=\frac{x^3y^2\sqrt{30y}}5$$

anonymous · Answer

it said I already chosen the best response an thanks a lot  you think you can help me on some more

anonymous · Answer

i picked yours you should get a medal

kc_kennylau · Answer

ofc what's your ques (brb)

anonymous · Answer

What is the simplest form of the radical expression?

kc_kennylau · Answer

is it $\Large4^3\sqrt{3x}+5^3\sqrt{10x}$ or $\Large4\sqrt[3]{3x}+5\sqrt[3]{10x}$?

anonymous · Answer

they look the same to me

kc_kennylau · Answer

is it 4^3sqrt(3x)+5^3sqrt(10x) or 4cbrt(3x)+5cbrt(10x)?

anonymous · Answer

|dw:1387070590449:dw| sorry that's 10x