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Mathematics 15 Online
OpenStudy (anonymous):

How can I know how many degrees a graph has shifted?

OpenStudy (anonymous):

OpenStudy (solomonzelman):

from the equation.

OpenStudy (solomonzelman):

Lets take \[\color{blue} {f(x)=2x}\]\[\color{blue} {f(x)=2\color{red} {(}x\color{red} {-a)}}\]a units right.\[\color{blue} {f(x)=2\color{red} {(}x\color{red} {+a)}}\]a units left.\[\color{blue} {f(x)=2x\color{red} {-a}}\]a units down.\[\color{blue} {f(x)=2x\color{red} {+a}}\]a units up.

OpenStudy (anonymous):

Well, the picture above was the answer to the problem. In the original problem, I am given no equations.

OpenStudy (solomonzelman):

Oh, I see, because I was confused what the question was looking at the first pic.

OpenStudy (anonymous):

Yeah, so I'm struggling with finding the original equation, well, for sine & cosine it's easier, since the origin for sine is always 0 and for cosine it is 1, but when it comes to finding shifts of x degrees, there I get confused.

OpenStudy (solomonzelman):

Oh yeah. I am not good at those....

OpenStudy (anonymous):

Haha ok, thank you for the help though.

OpenStudy (solomonzelman):

Glad I helped you somehow at least; anytime!

OpenStudy (the_fizicx99):

Try asking @robtobey @ranga @nincompoop and @shamil98 lol sorry I'm not this far ahead

OpenStudy (anonymous):

@SolomonZelman I think you have to convert to radians.

OpenStudy (anonymous):

I could be wrong, but this is what I think. I think this question can be done just by looking at the graph. If you look at the graphs of sin(x), cos(x) and tan(x), the graph they gave you looks a lot like tan(x). There's a point where the graph turns from being concave down to concave up. That point has been shifted to the right and down. See drawing to follow...

OpenStudy (anonymous):

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