Question

f(x)=x-4 g(x)=sqrt of x+2
what is the domain of (f+g) (x) ?

Answer 1

\[x \ge-2\]

Answer 2

if you meant sqrt(x+2)

Answer 3

yes

Answer 4

but x≥−2 is wrong

Answer 5

it's not wrong. Unless you meant sqrt(x) + 2, then the answer is x >/ 0

Answer 6

got it

Answer 7

If the functions f and g are:

\(f(x)=x-4\)
\( g(x)=\sqrt{x+2}\)

\( (f+g)(x) = f(x) + g(x) = x - 4 + \sqrt{x + 2} \)

The only restriction to the domain comes from \( \sqrt{x + 2} \)
The domain is:
\(x + 2 \ge 0\)
\(x \ge -2\)

If the functions f and g are:

\(f(x)=x-4\)
\( g(x)=\sqrt{x}+2\)

\( (f+g)(x) = f(x) + g(x) = x - 4 + \sqrt{x} + 2 =x + \sqrt{x} - 2 \)

The only restriction to the domain comes from \( \sqrt{x} \)
The domain is:
\(x \ge 0\)