Question

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Answer 1

@mathmale

Answer 2

Same with me!! I was just about to message him to tell him I LOVED his profile pic, and then it said he doesn't accept lol

Answer 3

Not a problem @Loser66
Thanks SO much for trying :D
I'm gonna log on later when maybe more mods are on lol

Answer 4

for the slope \[\huge\color{blue}{m=\frac{y_1-y_2}{x_1-x_2}}\]

Answer 5

Oh okay! @SolomonZelman

Answer 6

So that's slope, but what about slope intercept form?

Answer 7

\[\huge\color{blue}{\huge {\bbox[5pt,cyan,border:2px solid purple]{y=mx+b}}}\]

Answer 8

m= slope
b= y-intercept

Answer 9

Okay, so, knowing that, what do I do?

Answer 10

Let's try #6

Answer 11

For number 1)

plug in the points

Answer 12

(into the slope formula)

Answer 13

Oh oops yeah, someone on a different thread helped me with #1 and #4. I forgot to tell you that lol sorry

Answer 14

It's fine.

Answer 15

So you get the idea of how to do these questions?

Answer 16

Yes, thanks

Answer 17

Dear Pixie,
First, a quick review of three forms of equations of straight lines:

Slope-intercept form: y = mx + b, where m is the slope and (0,b) the y-intercept.

Point-slope form: y-b = m(x-a), where (a,b) is the point in question, through which the line passes, and m is the slope of the line.

General form: ax + by + c = 0, where a, b and c are constants.

Answer 18

Looks like you're supposed to express the equations of these lines in slope-intercept form for some, and in general form for others. That should not stop you from using the point-slope form, which can easily be converted to slope-intercept form.

For example, in Problem #4, the given point is (-5,-1), and the slope can be read off the graph as m=-2/3.

Substituting these values into the point-slope form [which is y-b = m(x-a)], we get:

y-(-1) = (-2/3)*(x-[-5]), or y+1 = (-2/3)*(x+5). Can you do the algebra necessary to solve this equation for y? The result will be the equation of the line in slope-intercept form.
(Answer: y = (-2/3)x - 13/3: slope is -2/3 and y intercept (b) is -13/3.

Answer 19

You could try solving the same problem using the slope-intercept form, but would have to estimate the value of b from the graph. I see that the red line crosses the y-axis at a little over 4 units below the origin, at (0,-13/3), to be exact. This is one reason why I'd prefer to use the slope-intercept form for this particular problem.

To complete this solution, using m=-2/3 and b=-13/3, directly from the given graph,
y = (-2/3)x -(13/3) (same as before).

Answer 20

WOW! THANK YOU THANK YOU THANK YOU