Question

A hypothetical cube grows so that the length of its sides are increasing at a rate of 4 m/min. How fast is the volume of the cube increasing when the sides are 5m each?

Answer 1

v=a^3 dv/dt=3a^2da/dt

Answer 2

let, side = a

volume is \[a^3\] so dv/dt will give \[(3a^2)da/dt\].

since \[da/dt\] = 4m/min.

now. dv/dt you can easily find right ??? @Nissa

Answer 3

so it'll be (3x5m^2)(4m/min)= 300m/min? I'm sorry I haven't looked over this in a while.

Answer 4

no, it will be \[300m^3/min\]

Answer 5

ohh okay, thank you

Answer 6

since it is the rate of change of volume...

Answer 7

that makes sense now.