Question

Prove: (can only work from the left side)
secx+tanx=cosx/1-sinx

Answer 1

You meant "Verify" and work one side independently.

Answer 2

\[Sec~x+Tan~x=\frac{Cos~x}{1}-Sin~x\]

Answer 3

Identities in RED.
Proofs in BLACK.
\[\color{red} {Secx=1~/~Cosx}\]\[\color{red} {Tan~x=Sin~x~/~Cos~x}\]

Answer 4

Yes my teacher will only let us work from the left side to prove the right side

Answer 5

\[\frac{1}{Cos~x}+\frac{Sin~x}{Cos~x}=\frac{Cos~x}{1}-Sin~x\]\[\frac{1+Sinx}{Cos~x}=\frac{Cos~x}{1}-Sin~x\]

Answer 6

I am not sure, i have to go

Answer 7

@NewK - what have tried so far?

Answer 8

I got as far as solomonzelman and got stuck there

Answer 9

from this step:\[\frac{1+\sin(x)}{\cos(x)}\]try multiplying numerator and denominator by \((1-\sin(x))\)

Answer 10

Thank you I got it!

Answer 11

yw :)