Question

Find the standard form of the equation of the parabola with a focus at (0, -3) and a directrix at y = 3.

Answer 1

The parabola has vertex (0,0) and is concave downward.

Answer 2

p=3

Answer 3

x^2=4py

Answer 4

I got y2 = -3x

Answer 5

Is it correct?

Answer 6

x^2=4py and p = 3
Replace p with 3

Answer 7

y2 = -12x, I am sure of it.

Answer 8

Thank You :)

Answer 9

The equation you have given opens to the left. The parabola you described opens down. Therefore the x term is the one that is squared.
Draw the graph of y^2=-12x
http://www.wolframalpha.com/input/?i=graph+y^2%3D-12x

Answer 10

See that is not the equation of a parabola whose directrix is a horizontal line.