Question

Q1: For a given company the relationship between price and number of units sold may be expressed by the equation:

p(x) = −x + 200, 0 < x < 200

p(x) denotes the unit price when selling x units.


The revenue may be calculated by

revenue = units sold *unit price.

a) The revenue R is given by the function R(x).
Account for this.

R(x) = -x ^2+ 200x , 0 < x < 200

What do I do here?

Answer 1

I don't think I understand what needs to be solved

Answer 2

Me neither. I'll just ask someone in school tomorrow. Thanks though.

Answer 3

Is this the whole question? Are you supposed to find profit?

Answer 4

Yes. I'm not really sure what is asked for me to do.

Answer 5

You're not asked to do anything. Maybe the teacher didn't finish the question.

Answer 6

I would guess you have to find the number of units to sell that will maximize revenue, that's the only thing that seems logical. You can either find the maximum on a calculator, or put it in standard form by completing the square.

Answer 7

https://www.google.com/search?q=R(x)+%3D+-x+%5E2%2B+200x&oq=R(x)+%3D+-x+%5E2%2B+200x&aqs=chrome..69i57.946j0j7&sourceid=chrome&espv=210&es_sm=93&ie=UTF-8#es_sm=93&espv=210&q=-x+%5E2%2B+200x

you can find the maximum value from here, when x=100, R = $10000

Answer 8

Aright, thanks. I just think the question is formulated really bad.

Answer 9

It's not just formulated bad, it's just missing the actual question.

Answer 10

True, thanks though. I'll find the maximum value and then ask my teacher tomorrow about the question.