In the figure below, segment CD is parallel to segment EF and point H bisects segment DE Prove ΔDIH ≅ ΔEGH.
Someone plsss
@nikato I said they were congruent by the asa postulate
DH=EH Definition of a Bisector Angle IDH = angle GEH Alternate interior angles Angle DHI = angle EHG Vertical angles are congruent Triangle DIH = Triangle EGH ASA postulate
Does that make sense?
Yup. Great job!
Thank you but one more thing
Sarah walks 20 feet away from her house and places a mirror on the ground. She backs 5 feet away from the mirror so that she can see the tip of the roof. Sarah's eyes are 4 feet above the ground. The angles between the top of the house, the mirror, and the ground and between Sarah's eyes, the mirror, and the ground are congruent as shown in the image:
Prove the triangles are similar.
I know you use the AA postulate not sure how though.
Wait, are the two angles marked in the diagram congruent?
I believe so
I'm not really sure how to prove. I guess I'm kinda assuming this
But the house should be perpendicular to the ground, making it a right angle
And same thing with the person, and since right angles are congruent, u can use AA
Thanks, I was thinking the same thing, but needed some reassurance. Thanks a lot! :)))))
Yea, I think that's the only thing u can do with the info u were given
Ye
Thanks again
No problem
@rumunerocks I'm going to close this question if that's ok with you.
no wait whats the height of the house then
If you want to find the height, set up a proportion becuz u already know the two triangles are similar. 4. x --= ----- 5. 20 Solve for x
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