Question

what is the inverse equations of the following:
a) y=sqrt(x-3)-1
b)y=(x-1)^2+3
c)y=2/x+5-1

Answer 1

Alright...so for the inverse equation...we just switch x and y... and solve for 'y' again...

for the first one...

\[\large y = \sqrt{x - 3} - 1\]
becomes
\[\large x = \sqrt{y - 3} - 1\]

Now add 1 to both sides...

\[\large x + 1 = \sqrt{y - 3}\]

Now you square both sides to get rid of that radical...

\[\large (x + 1)^2 = y - 3\]

And finally you add 3 to both sides...

\[\large y = (x + 1)^2 + 3\]

And that is your inverse...can you do the other 2?