Just 2 problems today! :D @jigglypuff314
Graph the points.
you can determine the perimeter without the need of the distance formula. you just have to graph the points connect them and look at the change between the points.
with that you can easily find your perimeter.
It's a square. But how do you find the perimeter?
Or how do you count each side?
The perimeter is the value of all the sides added, in this case distance between each points times 4. Because it is a square all sides are equal p = 4s
|dw:1387154671650:dw|\[distance formula: \sqrt{(x _{2}-x _{1})^{2} + (y _{2}-y _{1})^{2}}\]given points (x1, y1) and (x2, y2)
in addition to what em has shown. input (0,3), (3,0) as your values for the formula
Once you find the distance. Input that into: P = 4s where the distance = s to get your perimeter
Area=16 Perimeter=16?
No. Use the distance formula, since the square is rotated about the axis. Unfortunately you can't just look at the distance and find the length for this.
4.34 now what?
\[\huge d = \sqrt{(3-0)^2 + (0-3)^2} = \sqrt{18} = 3\sqrt{2}\]
Keep the form in radicals.
Ok
\[\huge P = 4s\] \[\huge P = 4(3\sqrt{2})\] \[\huge P = 12\sqrt{2}\]
SO perimeter is 16.97?
yep :)
And area?
3√2 times 3√2 =
18
:) And last one.
You don't really need our help on this one. Do the exact same thing, use the distance formula. If it is a square p = 4s if it is a rectangle p = 2L + 2W
It's a rhombus.
Okay. A square is type of rhombus. It's sides are also all equal. so calculuate the distance. and use p = 4s a = s^2
area wouldn't still be s^2 ... i think
ah, forgot. the area of rhombus is 1/2 ab where a and b are the diagonals
HOw do I calculate the distance?
use the same distance formula as before...
Radical29?
yep :)
So Area= 29?
Perimeter:21.54?
area is a bit different than a square... perimeter is right :)
find the two distances that are across from each other then area = (1/2)(diagonal1)(diagonal2)
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