Question

Simplify

(x^9)^0 (x^7)^2

Answer 1

\[(x^9)^0 (x^7)^2\]\[(x^9)^0=1\]\[ (x^7)^2~~~->~~~x^{14}\]

Answer 2

any thing to the
power of 0 is 1

Answer 3

Anything to the power of zero is 1 , excluding zero.
so
(x^9)^ 0 = 1
1 * (x^7)^2
\[\huge (x^m)^n = x^ {m*n}\]
so
1*x^14 = x^14

Answer 4

@Jared01, do you want us to show you why is \[(ANYTHING)~^0=1\]

Answer 5

\[s^0=s^{e-e}=s^e~/~s^e\]anything divided by itself is =1

Answer 6

(\[\frac{ m ^{-1}m ^{5} }{ m ^{-2} }\]

Answer 7

i need help with that

Answer 8

\[\huge x^n * x^m = x^{n+m}\]

Answer 9

\[\huge m^{-1} * m^5 = m^{-1+5}\]

Answer 10

after that you remember when you divide exponents you subtract.
\[\huge \frac{ x^m }{ x^n } = x^{m-n}\]