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Mathematics 16 Online
OpenStudy (anonymous):

y=4x^3(2x+1)^2 find dy/dx

OpenStudy (anonymous):

\[y= 4x^3 * (2x+1)^2\]

OpenStudy (anonymous):

Was just about to ask, lol. Alright, product rule then : )

OpenStudy (anonymous):

yeah do i just find the derrivate for all of them

OpenStudy (anonymous):

and for the y i just put y prime

OpenStudy (anonymous):

So we will need to do: \[f'(x)g(x) + f(x)g'(x)\] \[f(x) = 4x^{3}\] \[g(x) = (2x+1)^{2}\] If you know how to get the derivativesof f(x) and g(x), you can plug it all into the product rule formula I posted :3

OpenStudy (anonymous):

it will be

OpenStudy (anonymous):

12x^2 * (2x+1)^2 + 4x^3 * 2(2x+1) (2)

OpenStudy (anonymous):

Perfect ^_^ Unless you feel like cleaning it up a little bit, thats the answer.

OpenStudy (anonymous):

but the question ask for dy/dx tho

OpenStudy (anonymous):

does y become dy/dx?

OpenStudy (anonymous):

because i take derivate of everything

OpenStudy (anonymous):

That is dy/dx. And yes, it does. Youre technically takign the derivative of both sides of the equation y = 4x^3(2x+1)^2 the derivative of y on the left is dy/dx

OpenStudy (anonymous):

how would u clean that up btw would it be like 12x^2(2x+1)^2 + 4x^3 (8x+4)?

OpenStudy (anonymous):

Yeah, pretty much. Without actually multiplying things out i would leave it something like that.

OpenStudy (anonymous):

thank you so much !!!!

OpenStudy (anonymous):

Yep, np.

OpenStudy (anonymous):

i am new to this website if i want to post another question, how would i go about doing so?

OpenStudy (anonymous):

You can just close this question and then post a new one in the same way you posted this one.

OpenStudy (anonymous):

ok :D thanks !! will do

OpenStudy (anonymous):

Mhm.

OpenStudy (anonymous):

hi john.

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