y=4x^3(2x+1)^2 find dy/dx
\[y= 4x^3 * (2x+1)^2\]
Was just about to ask, lol. Alright, product rule then : )
yeah do i just find the derrivate for all of them
and for the y i just put y prime
So we will need to do: \[f'(x)g(x) + f(x)g'(x)\] \[f(x) = 4x^{3}\] \[g(x) = (2x+1)^{2}\] If you know how to get the derivativesof f(x) and g(x), you can plug it all into the product rule formula I posted :3
it will be
12x^2 * (2x+1)^2 + 4x^3 * 2(2x+1) (2)
Perfect ^_^ Unless you feel like cleaning it up a little bit, thats the answer.
but the question ask for dy/dx tho
does y become dy/dx?
because i take derivate of everything
That is dy/dx. And yes, it does. Youre technically takign the derivative of both sides of the equation y = 4x^3(2x+1)^2 the derivative of y on the left is dy/dx
how would u clean that up btw would it be like 12x^2(2x+1)^2 + 4x^3 (8x+4)?
Yeah, pretty much. Without actually multiplying things out i would leave it something like that.
thank you so much !!!!
Yep, np.
i am new to this website if i want to post another question, how would i go about doing so?
You can just close this question and then post a new one in the same way you posted this one.
ok :D thanks !! will do
Mhm.
hi john.
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