Question

Solve using any method http://i.imgur.com/zivJKwU.png

Answer 1

i take it you dont know how to solve quadratics?

Answer 2

I don't

Answer 3

just use the quadratic formula in this case because it cant be factored down to simple numbers

For ax^2 + bx + c = 0

x = [-b + sqrt(b^2-4ac)]/2a & [-b - sqrt(b^2-4ac)]/2a

Answer 4

have you seen this before?

Answer 5

no :/

Answer 6

that's how this one is done just substitute the values for a,b and c

in your case 2x^2 + x - 5 = 0

a = 2, b = 1 and c = -5

Answer 7

this will give you two values for x and they look nasty because they cant be simplified

Answer 8

so a = 2, b = 1 and c = -5 is the answer?

Answer 9

2x^2+x-5=0

Quadratic Formula

\[x=\frac{ -b+-\sqrt{b^2-4ac} }{ 2a }\]

a=2, b=1 and c=-5

Answer 10

\[-b (+,-)\sqrt{b ^{2}-4ac} / 2a\]
use this formula and replace the value of a,b,c by 2,1,-5
-1 +- rt.ov.1-4(2)(-5) / 4
-1+-rt.ov 41 /4

Answer 11

\[x=\frac{-1+- \sqrt{(-1)^2-4(2)(-5)} }{ 2(2) }\]

Answer 12

\[-1+\sqrt{41} / 4 and -1-\sqrt{41}/4\]
are its roots or the values of x

Answer 13

\[x=\frac{-1+- \sqrt{41} }{4 }\]

\[x=\frac{-1+\sqrt{41} }{ 4 }\]

or

Answer 14

Yea thats correct

Answer 15

\[x=\frac{-1-\sqrt{41} }{ 4 }\]

Answer 16

wait u have to solve it

Answer 17

Insert in the calculator and u its will show u the answer

Answer 18

rt ov41 is approximately equal to 6.4 now further you can solve it