Question

simplify : sin^2x/sec^2x-1

Answer 1

sec^2x-1=tan^2x

Answer 2

ik secis 1/cos so I can flip with squareing but idk if im right I think the answer is sin^2xtan^2x I guess im wrong lol

Answer 3

So I get sin^2x/tan^2x. Since tanx = sinx/cosx, tan^2x = sin^2x/cos^2x

Answer 4

sin^2x/(sin^2x/cos^2x)= cos^2x

Answer 5

is this sin^2x/(sec^2-1)?

Answer 6

sorry i meant is sec^2x - 1 on the bottom line?

Answer 7

That is what I am assuming, but I could be wrong. @cohesivesandman ?

Answer 8

sec^2 x -1

Answer 9

All of that is in the denominator?

Answer 10

ok, then joanna is correct

Answer 11

yes